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Yahoo! Answers - Sol. of 14.8M of NH3. How many mL of sol should ...

Best Answer: M1V1=M2V2 14.8 * V1 = 0.25*100 V1 = 0.25*100/14.8 V1 = 1.689ml M1V1= M2V2 14.8*10 = M2*250 M2 = 14.8*10/250 M2 = 0.592M

0.1 M HCL solution

Author: Topic: 0.1 M HCL solution (Read 15905 times) 0 Members and 1 Guest are viewing this topic.

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New Senior Secondary Learning as well as Teaching Resource List Subject Mathematics NSS Subject Resource List S4 Mathematics Summer Holiday Homework 2010 Mathematics ...

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What volume of 2.0 M NaCl is required to prepare 150 mL of 0.10 M ...

Best Answer: a. 7.5 mL b/c .10 M means .10 mol/1L which in proportion is 0.10mol/1000mL=xmol/150mL which then means there are .015 moles of NaCl Then we set up a new ...

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Yahoo! Canada Answers - A mole of X reacts at a constant pressure ...

Best Answer: Given data H0 = -75.0 kJ Pressure, P = 43.0 atm = 43 atm * 101325 Pa/1 atm = 4356975 Pa = 4356975 N / m2 Volume change, V = 2.0 L - 5.0 L = -3.0 L ...

0.1 M HCL solution

Author: Topic: 0.1 M HCL solution (Read 15905 times) 0 Members and 1 Guest are viewing this topic.

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How do I make a 10 millimolar solution of HCl (in 1 Litre of Water ...

Thanks for your answer Dr Buzz.. I calculated that at 1st but I need the HCl amount in mL. So i suspect im meant to use the V1 x M1 = V2 x M2 equation..